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Mathematics Extension 2

Stage 6 · HSC questions by topic

About this subject

Mathematics Extension 2

Atlas organises human-reviewed questions against the NSW Stage 6 Mathematics Extension 2syllabus. Every published question retains its exam source and page.

Syllabus: NESA Stage 6 (2017)
Explore the NESA Stage 6 (2017) syllabus topics

Proof

  • The Nature of Proof
  • Further Proof by Mathematical Induction

Vectors

  • Introduction to three-dimensional vectors
  • Further operations with three-dimensional vectors
  • Vectors and vector equations of lines

Complex Numbers

  • Arithmetic of complex numbers
  • Geometric representation of a complex number
  • Other representations of complex numbers
  • Solving equations with complex numbers
  • Geometrical implications of complex numbers

Calculus

  • Further Integration

Mechanics

  • Simple harmonic motion
  • Modelling motion without resistance
  • Resisted motion
  • Projectiles and resisted motion
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290 questions found

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2022Trial
Q11 (c)

In the Argand diagram below, OA→=z1\overrightarrow{OA}=z_1OA=, , and . Express in terms of and .

z1​
OB→=z2\overrightarrow{OB}=z_2OB=z2​
OA=OBOA=OBOA=OB
AC→=CB→\overrightarrow{AC}=\overrightarrow{CB}AC=CB
OC→\overrightarrow{OC}OC
z1z_1z1​
z2z_2z2​
2 marks
Short answer
2022Trial
Q11 (d) (ii)

Using the points defined in part (d), find ∣CB→∣|\overrightarrow{CB}|∣CB∣.

2 marks
Short answer
2022HSC
Q11 (f)

Using the substitution t=tan⁡x2t=\tan\frac{x}{2}t=tan2x​, find
∫dx1+cos⁡x−sin⁡x.\int\frac{dx}{1+\cos x-\sin x}.∫1+cosx−sinxdx​.

3 marks
Short answer
2022HSC
Q11 (e)

Let ℓ1\ell_1ℓ1​ be the line with equation
(xy)=(−17)+λ(32),λ∈R.\begin{pmatrix}x\\y\end{pmatrix}=\begin{pmatrix}-1\\7\end{pmatrix}+\lambda\begin{pmatrix}3\\2\end{pmatrix},\quad \lambda\in\mathbb R.(xy​)=(−17​)+λ(

The line ℓ2\ell_2ℓ2​ passes through the point A(−6,5)A(-6,5)A(−6,5) and is parallel to ℓ1\ell_1ℓ1​. Find the equation of the line in the form .

2 marks
Short answer
2022HSC
Q11 (c) (ii)

Hence, find the exact value of (−3+i)10(-\sqrt3+i)^{10}(−3​+i)10, giving your answer in the form x+iyx+iyx+iy.

2 marks
Extended response
2022HSC
Q11 (c) (i)

Write the complex number −3+i-\sqrt3+i−3​+i in exponential form.

2 marks
Short answer
2022HSC
Q11 (b)

Evaluate ∫sin⁡3(2x)cos⁡(2x) dx\displaystyle\int \sin^3(2x)\cos(2x)\,dx∫sin3(2x)cos(2x)dx.

2 marks
Short answer
2022Trial
Q11 (a) (i)

If z=−3+iz=-\sqrt3+iz=−3​+i and w=1+iw=1+iw=1+i, find Arg⁡(zw)\operatorname{Arg}(zw)Arg(zw) in terms of π\piπ.

2 marks
Short answer
2022Trial
Q11 (a) (ii)

If z=−3+iz=-\sqrt3+iz=−3​+i and w=1+iw=1+iw=1+i, write zw\frac zwwz​ in the form x+iyx+iyx+iy, where xxx and yyy are real numbers.

2 marks
Short answer
2022Trial
Q11 (a) (i)

Find −1+i31+i\frac{-1+i\sqrt3}{1+i}1+i−1+i3​​ in Cartesian form.

2 marks
Short answer
2022HSC
Q11 (a)

Express 3−i2+i\dfrac{3-i}{2+i}2+i3−i​ in the form x+iyx+iyx+iy, where xxx and yyy are real numbers.

2 marks
Short answer
2022Trial
Q11 (b) (i)

By letting (x+iy)2=7+24i(x+iy)^2=7+24i(x+iy)2=7+24i, where x,yx,yx,y are real, find 7+24i\sqrt{7+24i}7+24i​ in Cartesian form.

3 marks
Short answer
2022HSC
Q11 (d)

A triangle is formed in three-dimensional space with vertices A(1,−1,2)A(1,-1,2)A(1,−1,2), B(0,2,−1)B(0,2,-1)B(0,2,−1) and C(2,1,1)C(2,1,1)C(2,1,1). Find the size of ∠ABC\angle ABC∠ABC, giving your answer to the nearest degree.

3 marks
Short answer
2022Trial
Q11 (a) (ii)

Express −1+i3-1+i\sqrt3−1+i3​ and 1+i1+i1+i in modulus/argument form.

2 marks
Short answer
2022Trial
Q11 (c)

Find the vector equation for the sphere x2+4x+y2−6y+z2=12x^2+4x+y^2-6y+z^2=12x2+4x+y2−6y+z2=12.

2 marks
Short answer
2022Trial
Q11 (a) (iii)

Hence find the exact value of tan⁡5π12\tan\frac{5\pi}{12}tan125π​.

2 marks
Short answer
2022Trial
Q11 (d)

Using De Moivre’s Theorem, find the 3 cube roots of −42+4i2-4\sqrt2+4i\sqrt2−42​+4i2​. Leave your answers in modulus/argument form.

2 marks
Short answer
2022Trial
Q11 (b) (ii)

Hence solve the equation z2−3iz−(4+6i)=0z^2-3iz-(4+6i)=0z2−3iz−(4+6i)=0.

2 marks
Short answer
2022Trial
Q11 (d) (i)

Point AAA has position vector 8i+13j−2k8\mathbf i+13\mathbf j-2\mathbf k8i+13j−2k, point BBB has position vector 10i+14j−4k10\mathbf i+14\mathbf j-4\mathbf k10i+14j−4k, and point CCC has position vector 9i+9j+6k9\mathbf i+9\mathbf j+6\mathbf k9i+9j+6k. Find AB→\overrightarrow{AB}AB.

1 mark
Short answer
2022Trial
Q12 (a) (i)

Find AAA and BBB such that
15x2−2x−15=Ax+3+Bx−5.\frac{15}{x^2-2x-15}=\frac A{x+3}+\frac B{x-5}.x2−2x−1515​=x+3A​+x−5B​.

2 marks
Short answer
2022Trial
Q12 (a) (ii)

Hence, or otherwise, find
∫x2−2xx2−2x−15 dx.\int\frac{x^2-2x}{x^2-2x-15}\,dx.∫x2−2x−15x2−2x​dx.

2 marks
Short answer
2022Trial
Q12 (b)

Evaluate
∫0π/4sec⁡4xtan⁡2x dx.\int_0^{\pi/4}\sec^4x\tan^2x\,dx.∫0π/4​sec4xtan2xdx.

3 marks
Short answer
2022Trial
Q12 (c)

Use proof by contrapositive to prove that: If a2−2a+7a^2-2a+7a2−2a+7 is even, then aaa is odd.

3 marks
Short answer
2022Trial
Q12 (c) (i)

Find AAA, BBB and CCC so that
Ax−1+Bx+Cx2+4=−7x−18(x−1)(x2+4).\frac{A}{x-1}+\frac{Bx+C}{x^2+4}=\frac{-7x-18}{(x-1)(x^2+4)}.x−1A​+x2+4Bx+C​

3 marks
Short answer
2022Trial
Q12 (b)

Find ∫12+cos⁡x dx\displaystyle\int\frac{1}{2+\cos x}\,dx∫2+cosx1​dx.

3 marks
Short answer
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3
2
​
)
,
λ
∈
R.
ℓ2\ell_2ℓ2​
y=mx+cy=mx+cy=mx+c
=
(x−1)(x2+4)−7x−18​.