ATLASBeta

Subjects

Ancient HistoryComing soon
BiologyBusiness Studies
ChemistryComing soon
CAFSEconomics
EngineeringComing soon
English AdvancedEnglish Ext 1English Standard
English StudiesComing soon
Enterprise ComputingComing soon
Geography
Health & MovementComing soon
Legal StudiesMaths AdvancedMathematics Ext 1Mathematics Ext 2
Maths Standard 1Coming soon
Maths Standard 2Coming soon
Modern HistoryComing soon
PhysicsReligion IReligion II
Visual ArtsComing soon
Save your favourites

Accounts and progress tracking are coming later.

Coming later

Mathematics Extension 2

Stage 6 · HSC questions by topic

About this subject

Mathematics Extension 2

Atlas organises human-reviewed questions against the NSW Stage 6 Mathematics Extension 2syllabus. Every published question retains its exam source and page.

Syllabus: NESA Stage 6 (2017)
Explore the NESA Stage 6 (2017) syllabus topics

Proof

  • The Nature of Proof
  • Further Proof by Mathematical Induction

Vectors

  • Introduction to three-dimensional vectors
  • Further operations with three-dimensional vectors
  • Vectors and vector equations of lines

Complex Numbers

  • Arithmetic of complex numbers
  • Geometric representation of a complex number
  • Other representations of complex numbers
  • Solving equations with complex numbers
  • Geometrical implications of complex numbers

Calculus

  • Further Integration

Mechanics

  • Simple harmonic motion
  • Modelling motion without resistance
  • Resisted motion
  • Projectiles and resisted motion
Filters

More filters

290 questions found

List
2022Trial
Q3

The straight line
(xyz)=(143)+λ(−112)\begin{pmatrix}x\\y\\z\end{pmatrix}=\begin{pmatrix}1\\4\\3\end{pmatrix}+\lambda\begin{pmatrix}-1\\1\\2\end{pmatrix} has symmetric (or Cartesian) equation

​xyz​​=
​143​​+
λ​−112​​

A. x−1=y−4=z−32x-1=y-4=\frac{z-3}{2}x−1=y−4=2z−3​

B. x−1=y−4=z+32x-1=y-4=\frac{z+3}{2}x−1=y−4=2z+3​

C. 1−x=y−4=z−321-x=y-4=\frac{z-3}{2}1−x=y−4=2z−3​

D. 1−x=y−4=z+321-x=y-4=\frac{z+3}{2}1−x=y−4=2z+3​

1 mark
Multiple choice
2022HSC
Q3

Let AAA, BBB, PPP be three points in three-dimensional space with A≠BA\ne BA=B.

If PPP is on the line ABABAB, then there exists a real number λ\lambdaλ such that AP→=λAB→\overrightarrow{AP}=\lambda\overrightarrow{AB}AP.

Which of the following is the contrapositive of this statement?

A. If for all real numbers λ\lambdaλ, AP→=λAB→\overrightarrow{AP}=\lambda\overrightarrow{AB}AP=λAB, then is on the line . B. If for all real numbers , , then is not on the line . C. If there exists a real number such that , then is on the line . D. If there exists a real number such that , then is not on the line .

1 mark
Multiple choice
2022Trial
Q4

Given
OA→=[110],OB→=[2−11],OC→=[3μλ],\overrightarrow{OA}=\begin{bmatrix}1\\1\\0\end{bmatrix},\quad \overrightarrow{OB}=\begin{bmatrix}2\\-1\\1\end{bmatrix},\quad \overrightarrow{OC}=\begin{bmatrix}3\\\mu\\\lambda\end{bmatrix},OA=​110​
where OOO is the origin, what are the values of μ\muμ and λ\lambdaλ if AAA, BBB and CCC are collinear?

A. μ=3, λ=2\mu=3,\ \lambda=2μ=3, λ=2

B. μ=−3, λ=2\mu=-3,\ \lambda=2μ=−3, λ=2

C. μ=3, λ=−2\mu=3,\ \lambda=-2μ=3, λ=−2

D. μ=−3, λ=−2\mu=-3,\ \lambda=-2μ=−3, λ=−2

1 mark
Multiple choice
2022HSC
Q4

Of the following expressions, which one need NOT contain a term involving a logarithm in its anti-derivative?

A. x+2x2+4x+5\dfrac{x+2}{x^2+4x+5}x2+4x+5x+2​

B. x+2x2−4x−5\dfrac{x+2}{x^2-4x-5}x2−4x−5x+2​

C. x−1x3−x2+x−1\dfrac{x-1}{x^3-x^2+x-1}x3−x2+x−1x−1​

D. x+1x3−x2+x−1\dfrac{x+1}{x^3-x^2+x-1}x3−x2+x−1x+1​

1 mark
Multiple choice
2022Trial
Q4

The equation of the curve in 3-dimensional space below is

A. x=t2x=t^2x=t2, y=ty=ty=t, z=0z=0z=0

B. x=0x=0x=0, y=t2y=t^2y=t2, z=tz=tz=t

C. x=0x=0x=0, y=ty=ty=t, z=t2z=t^2z=t2

D. x=t2x=t^2x=t2, y=t2y=t^2y=t2, z=0z=0z=

1 mark
Multiple choice
2022Trial
Q5

One of the roots of iz2+3z+3−11i=0iz^2+3z+3-11i=0iz2+3z+3−11i=0 is 3+2i3+2i3+2i. What is the other root?

A. −2i-2i−2i
B. −3+i-3+i−3+i
C. 3−2i3-2i3−2i
D. −5−3i-5-3i−5−

1 mark
Multiple choice
2022HSC
Q5

If ∫axf(t) dt=g(x)\displaystyle\int_a^x f(t)\,dt=g(x)∫ax​f(t)dt=g(x), which of the following is a primitive of f(x)g(x)f(x)g(x)f(x)g(x)?

A. 12[f(x)]2\frac12[f(x)]^221​[f(x)]2

B. 12[f′(x)]2\frac12[f'(x)]^221​[f′(x)]2

C. 12[g(x)]2\frac12[g(x)]^221​[g(x)]2

D. 12[g′(x)]2\frac12[g'(x)]^221​[g′(x)]2

1 mark
Multiple choice
2022Trial
Q5

∫16x−x2 dx=\int\frac{1}{\sqrt{6x-x^2}}\,dx=∫6x−x2​1​dx=

A. sin⁡−1(x6)+C\sin^{-1}\left(\frac{x}{\sqrt6}\right)+Csin−1(6​

B. sin⁡−1(x6)+C\sin^{-1}\left(\frac{x}{6}\right)+Csin−1(6x​)+C

C. sin⁡−1(x−36)+C\sin^{-1}\left(\frac{x-3}{\sqrt6}\right)+Csin−1(6

D. sin⁡−1(x−33)+C\sin^{-1}\left(\frac{x-3}{3}\right)+Csin−1(3x−3​)+C

1 mark
Multiple choice
2022HSC
Q6

It is known that a particular complex number zzz is NOT a real number. Which of the following could be true for this number zzz?

A. zˉ=iz\bar z=izzˉ=iz

B. zˉ=∣z2∣\bar z=|z^2|zˉ=∣z2∣

C. Re⁡(iz)=Im⁡(z)\operatorname{Re}(iz)=\operatorname{Im}(z)Re(iz)=Im(z)

D. Arg⁡(z3)=Arg⁡(z)\operatorname{Arg}(z^3)=\operatorname{Arg}(z)Arg(z3)=Arg(z)

1 mark
Multiple choice
2022Trial
Q6

Which of the following is the locus of zzz such that
arg⁡(z+3i)−arg⁡(z−i)=π2?\arg(z+3i)-\arg(z-i)=\frac\pi2?arg(z+3i)−arg(z−i)=2π​?

1 mark
Multiple choice
2022Trial
Q6

If f(x)f(x)f(x) is even then
∫−aaf(x) dx=\int_{-a}^{a}f(x)\,dx=∫−aa​f(x)dx=

A. 2∫0af(a−x) dx2\int_0^a f(a-x)\,dx2∫0a​f(a−x)dx

B. 2∫0−af(a−x) dx2\int_0^{-a} f(a-x)\,dx2∫0−a​f(a−x)dx

C. 2∫a0f(x) dx2\int_a^0 f(x)\,dx2∫a0​f(x)dx

D. All of the above.

1 mark
Multiple choice
2022Trial
Q7

z2+pz+q=0z^2+pz+q=0z2+pz+q=0, where p,qp,qp,q are real, has one solution z=3−2iz=3-2iz=3−2i. The values of ppp and qqq are:

A. p=6p=6p=6, q=13q=13q=13

B. p=−6p=-6p=−6, q=13q=13q=13

C. p=−6p=-6p=−6, q=−13q=-13q=−13

D. p=−6p=-6p=−6, q=−13q=-13q=−13

1 mark
Multiple choice
2022HSC
Q7

Consider the statement PPP.

PPP: For all integers n≥1n\ge1n≥1, if nnn is a prime number then n(n+1)2\dfrac{n(n+1)}22n(n+1)​ is a prime number.

Which of the following is true about this statement and its converse?

A. The statement PPP and its converse are both true.
B. The statement PPP and its converse are both false.
C. The statement PPP is true and its converse is false.
D. The statement PPP is false and its converse is true.

1 mark
Multiple choice
2022Trial
Q7

Which of the following definite integrals has a positive value?

A. ∫−1/21/2x3(1+cos⁡x) dx\displaystyle\int_{-1/2}^{1/2}x^3(1+\cos x)\,dx∫−1/21/2​x3(1+cosx)dx

B. ∫−1/21/2sin⁡−1x1+x4 dx\displaystyle\int_{-1/2}^{1/2}\frac{\sin^{-1}x}{1+x^4}\,dx∫−1/21/2​1+x

C. ∫−1/21/2cos⁡−1xe−x2 dx\displaystyle\int_{-1/2}^{1/2}\frac{\cos^{-1}x}{e^{-x^2}}\,dx∫−1/21/2​e−

D. ∫−1/21/2tan⁡−1xex+e−x dx\displaystyle\int_{-1/2}^{1/2}\frac{\tan^{-1}x}{e^x+e^{-x}}\,dx∫−1/21/2​e

1 mark
Multiple choice
2022HSC
Q8

As a projectile of mass mmm kilograms travels through air, it experiences a frictional force. The magnitude of this force is proportional to the square of the speed vvv of the projectile. The constant of proportionality is the positive number kkk. The position of the particle at time ttt is denoted by (xy)\begin{pmatrix}x\\y\end{pmatrix}(xy​). The acceleration due to gravity is g m s−2g\,\mathrm{m\,s^{-2}}gms−2.

Based on Newton’s laws of motion, which equation models the motion of this projectile?

A. (0−mg)+kv(x˙y˙)=m(x¨y¨)\begin{pmatrix}0\\-mg\end{pmatrix}+kv\begin{pmatrix}\dot x\\\dot y\end{pmatrix}=m\begin{pmatrix}\ddot x\\\ddot y\end{pmatrix}(0−mg​)

B. (0−mg)−kv(x˙y˙)=m(x¨y¨)\begin{pmatrix}0\\-mg\end{pmatrix}-kv\begin{pmatrix}\dot x\\\dot y\end{pmatrix}=m\begin{pmatrix}\ddot x\\\ddot y\end{pmatrix}(0−mg​)

C. (0−mg)+kv2(x˙y˙)=m(x¨y¨)\begin{pmatrix}0\\-mg\end{pmatrix}+kv^2\begin{pmatrix}\dot x\\\dot y\end{pmatrix}=m\begin{pmatrix}\ddot x\\\ddot y\end{pmatrix}(0−mg​)

D. (0−mg)−kv2(x˙y˙)=m(x¨y¨)\begin{pmatrix}0\\-mg\end{pmatrix}-kv^2\begin{pmatrix}\dot x\\\dot y\end{pmatrix}=m\begin{pmatrix}\ddot x\\\ddot y\end{pmatrix}(0−mg​)

1 mark
Multiple choice
2022Trial
Q8

If the complex number zzz has ∣z∣>1|z|>1∣z∣>1 and π2<Arg⁡(z)<π\frac\pi2<\operatorname{Arg}(z)<\pi2π​<Arg(z)<π, and OA→=z\overrightarrow{OA}=zOA=z, then if the two square roots of zzz are OP→\overrightarrow{OP}OP and OQ→\overrightarrow{OQ}OQ​, PPP and QQQ could be at:

1 mark
Multiple choice
2022Trial
Q8

Given that zzz is a complex number such that Re⁡(z)≠0\operatorname{Re}(z)\ne0Re(z)=0, which of the following is equivalent to
4zzˉ(z+zˉ)2?\frac{4z\bar z}{(z+\bar z)^2}?(z+zˉ)24zzˉ​?

A. 1+(Im⁡(z)Re⁡(z))21+\left(\frac{\operatorname{Im}(z)}{\operatorname{Re}(z)}\right)^21+(Re(z)Im(z)​) B. C. D.

1 mark
Multiple choice
2022HSC
Q9

Let AAA and BBB be two distinct points in three-dimensional space. Let MMM be the midpoint of ABABAB.

Let S1S_1S1​ be the set of all points PPP such that AP→⋅BP→=0\overrightarrow{AP}\cdot\overrightarrow{BP}=0AP⋅BP.

Let S2S_2S2​ be the set of all points NNN such that ∣AN→∣=∣MN→∣|\overrightarrow{AN}|=|\overrightarrow{MN}|∣AN.

The intersection of S1S_1S1​ and S2S_2S2​ is the circle SSS.

What is the radius of the circle SSS?

A. ∣AB→∣2\dfrac{|\overrightarrow{AB}|}{2}2∣AB∣​
B. C. D.

1 mark
Multiple choice
2022Trial
Q9

Which of the following is the negation of the statement:

“∀p∈P\forall p\in P∀p∈P, ppp is of the form 4m+1⇒p4m+1\Rightarrow p4m+1⇒p can be written as a sum of two squares”?

A. ∀p∈P\forall p\in P∀p∈P, ppp is of the form 4m+14m+14m+1 and ppp cannot be written as a sum of two squares.
B. ∃p∈P\exists p\in P, is not of the form and can be written as a sum of two squares. C. , is not of the form or cannot be written as a sum of two squares. D. , is of the form and cannot be written as a sum of two squares.

1 mark
Multiple choice
2022Trial
Q9

The acceleration of a particle is given by x¨=sec⁡2x\ddot{x}=\sec^2xx¨=sec2x, where xxx is the displacement in metres. The rule for the velocity could be:

A. v=tan⁡xv=\sqrt{\tan x}v=tanx​

B. v=2tan⁡xv=\sqrt{2\tan x}v=2tanx​

C. v=tan⁡xv=\tan xv=tanx

D. v=2tan⁡xv=2\tan xv=2tanx

1 mark
Multiple choice
2022HSC
Q10

A particle is moving vertically in a resistive medium under the influence of gravity. The resistive force is proportional to the velocity of the particle.

The initial speed of the particle is NOT zero.

Which of the following statements about the motion of the particle is always true?

A. If the particle is initially moving downwards, then its speed will increase.
B. If the particle is initially moving downwards, then its speed will decrease.
C. If the particle is initially moving upwards, then its speed will eventually approach a terminal speed.
D. If the particle is initially moving upwards, then its speed will not eventually approach a terminal speed.

1 mark
Multiple choice
2022Trial
Q10

In the diagram, the vectors OP→\overrightarrow{OP}OP and OQ→\overrightarrow{OQ}OQ​ represent the complex numbers z1z_1z1​ and z2z_2z2​ respectively. If
z2z1=3 i,\frac{z_2}{z_1}=\sqrt3\,i,z1​z2​​=
what is the value of
∣z1+z2z2−z1∣?\left|\frac{z_1+z_2}{z_2-z_1}\right|?​z2​−z

A. 111
B. 3\sqrt33​
C. 13\frac1{\sqrt3} D.

1 mark
Multiple choice
2022Trial
Q10

A particle moves with simple harmonic motion with equation x=asin⁡ntx=a\sin ntx=asinnt. It first returns to its starting point after π3\frac\pi33π​ seconds and is travelling at 151515 m/s forwards at this time. The displacement of the particle is given by

A. x=52sin⁡6tx=\frac52\sin6tx=25​sin6t

B. x=−52sin⁡6tx=-\frac52\sin6tx=−25​sin6t

C. x=5sin⁡3tx=5\sin3tx=5sin3t

D. x=−5sin⁡3tx=-5\sin3tx=−5sin3t

1 mark
Multiple choice
2022Trial
Q11 (d) (iii)

Using the points defined in part (d), what is the size of the acute angle between AB→\overrightarrow{AB}AB and CB→\overrightarrow{CB}CB? Answer correct to the nearest degree.

3 marks
Short answer
2022Trial
Q11 (e)

Find
∫15+4x−x2 dx.\int\frac{1}{\sqrt{5+4x-x^2}}\,dx.∫5+4x−x2​1​dx.

2 marks
Short answer
← PreviousPage 4 of 12Next →
=
λAB
PPP
ABABAB

λ\lambdaλ
AP→≠λAB→\overrightarrow{AP}\ne\lambda\overrightarrow{AB}AP=λAB
PPP
ABABAB

λ\lambdaλ
AP→=λAB→\overrightarrow{AP}=\lambda\overrightarrow{AB}AP=λAB
PPP
ABABAB

λ\lambdaλ
AP→≠λAB→\overrightarrow{AP}\ne\lambda\overrightarrow{AB}AP=λAB
PPP
ABABAB
​
,
OB
=
​2−11​​,OC=
​3μλ​​,
0
3
i
x
​
)
+
C
​
x−3
​
)
+
C
4
sin−1x
​
d
x
x2
cos−1x
​
d
x
x
+
e−x
tan−1x
​
d
x
+
kv(x˙y˙​​)=
m(x¨y¨​​)
−
kv(x˙y˙​​)=
m(x¨y¨​​)
+
kv2(x˙y˙​​)=
m(x¨y¨​​)
−
kv2(x˙y˙​​)=
m(x¨y¨​​)
2

4(Im⁡(z)×Re⁡(z))4(\operatorname{Im}(z)\times\operatorname{Re}(z))4(Im(z)×Re(z))

4(1+[Im⁡(z)+Re⁡(z)]2)4\left(1+[\operatorname{Im}(z)+\operatorname{Re}(z)]^2\right)4(1+[Im(z)+Re(z)]2)

2Im⁡(z)[Re⁡(z)]2\displaystyle\frac{2\operatorname{Im}(z)}{[\operatorname{Re}(z)]^2}[Re(z)]22Im(z)​
=
0
∣
=
∣MN∣
∣AB→∣4\dfrac{|\overrightarrow{AB}|}{4}
4∣AB∣​

3∣AB→∣2\dfrac{\sqrt3|\overrightarrow{AB}|}{2}23​∣AB∣​

3∣AB→∣4\dfrac{\sqrt3|\overrightarrow{AB}|}{4}43​∣AB∣​
∃p∈P
ppp
4m+14m+14m+1
ppp

∀p∈P\forall p\in P∀p∈P
ppp
4m+14m+14m+1
ppp

∃p∈P\exists p\in P∃p∈P
ppp
4m+14m+14m+1
ppp
3​i,
1
​
z1​+z2​
​
​
?
3​
1
​

3+13−1\frac{\sqrt3+1}{\sqrt3-1}3​−13​+1​