2023HSCQ9A particle travels along a curve from OOO to EEE in the xyxyxy-plane, as shown in the diagram. The position vector is r\mathbf r, velocity is , and acceleration is . While travelling from to , the particle is always slowing down. Which of the following is consistent with the motion?
2023HSCQ10Consider three-dimensional vectors a=OA→\mathbf a=\overrightarrow{OA}a=OA, b=OB→\mathbf b=\overrightarrow{OB}b=OB and c=OC→\mathbf c=\overrightarrow{OC}c=OC satisfying a⋅b=1\mathbf a\cdot\mathbf b=1a⋅b=1, b⋅c=2\mathbf b\cdot\mathbf c=2b⋅c=2, and c⋅a=3\mathbf c\cdot\mathbf a=3c⋅a=3. Which statement is true? A. Two of a,b,c\mathbf a,\mathbf b,\mathbf ca,b,c could be unit vectors. B. The points A,B,CA,B,CA,B,C could lie on a sphere centred at OOO. C. For any three-dimensional vector a\mathbf aa, vectors can be found satisfying the conditions. D. For all such vectors, there exist positive reals such that .1 markMultiple choice
2023TrialQ11 (e) (iii)Using vector methods, show that the length of the perpendicular from MMM to ON→\overrightarrow{ON}ON is 225 units.\sqrt{\frac{22}{5}}\text{ units}.522 units.3 marksShort answer
2023HSCQ11 (b)Find the angle between the vectors a=i+2j−3k\mathbf a=\mathbf i+2\mathbf j-3\mathbf ka=i+2j−3k and b=−i+4j+2k\mathbf b=-\mathbf i+4\mathbf j+2\mathbf kb=−i+4j+2k, giving your answer to the nearest degree.3 marksShort answer
2023TrialQ11 (d)Find the equations of a sphere whose centre is at (1,0,1)(1,0,1)(1,0,1) and touches the line r⃗=(312)+λ(212),λ∈R.\vec r=\begin{pmatrix}3\\1\\2\end{pmatrix}+\lambda\begin{pmatrix}2\\1\\2\end{pmatrix},\qquad \lambda\in\mathbb{R}.r=33 marksShort answer
2023TrialQ11 (e) (ii)Using the diagram and information from part (e), calculate the angle between MD→\overrightarrow{MD}MD and ON→\overrightarrow{ON}ON.2 marksShort answer
2023TrialQ13 (d) (ii)Another line, ℓ2\ell_2ℓ2, is defined by the vector equation r⃗=(012)+λ(a1−1),λ,a∈R.\vec r=\begin{pmatrix}0\\1\\2\end{pmatrix}+\lambda\begin{pmatrix}a\\1\\-1\end{pmatrix},\qquad \lambda,a\in\mathbb{R}.r=0 Find the possible values of aaa when the angle between ℓ1\ell_1ℓ1 and ℓ2\ell_2ℓ2 is π4\frac{\pi}{4}.2 marksShort answer
2022TrialQ1What is the unit vector in the same direction as a⃗=2i+j−3k\vec a=2\mathbf i+\mathbf j-3\mathbf ka=2i+j−3k? A. −114[21−3]-\frac1{14}\begin{bmatrix}2\\1\\-3\end{bmatrix}−141 B. C. D. 1 markMultiple choice
2022HSCQ9Let AAA and BBB be two distinct points in three-dimensional space. Let MMM be the midpoint of ABABAB. Let S1S_1S1 be the set of all points PPP such that AP→⋅BP→=0\overrightarrow{AP}\cdot\overrightarrow{BP}=0AP⋅BP. Let S2S_2S2 be the set of all points NNN such that ∣AN→∣=∣MN→∣|\overrightarrow{AN}|=|\overrightarrow{MN}|∣AN. The intersection of S1S_1S1 and S2S_2S2 is the circle SSS. What is the radius of the circle SSS? A. ∣AB→∣2\dfrac{|\overrightarrow{AB}|}{2}2∣AB∣ B. C. D. 1 markMultiple choice
2022TrialQ11 (d) (ii)Using the points defined in part (d), find ∣CB→∣|\overrightarrow{CB}|∣CB∣.2 marksShort answer
2022HSCQ11 (d)A triangle is formed in three-dimensional space with vertices A(1,−1,2)A(1,-1,2)A(1,−1,2), B(0,2,−1)B(0,2,-1)B(0,2,−1) and C(2,1,1)C(2,1,1)C(2,1,1). Find the size of ∠ABC\angle ABC∠ABC, giving your answer to the nearest degree.3 marksShort answer
2022TrialQ11 (d) (iii)Using the points defined in part (d), what is the size of the acute angle between AB→\overrightarrow{AB}AB and CB→\overrightarrow{CB}CB? Answer correct to the nearest degree.3 marksShort answer
2022HSCQ14 (a) (i)The two non-parallel vectors u⃗\vec uu and v⃗\vec vv satisfy λu⃗+μv⃗=0⃗\lambda\vec u+\mu\vec v=\vec0λu+μv for some real numbers λ\lambdaλ and μ\muμ. Show that λ=μ=0\lambda=\mu=0λ=μ=0.2 marksShort answer
2022TrialQ15 (c) (ii)It is given that c⃗=[140]+t[−115]\vec c=\begin{bmatrix}1\\4\\0\end{bmatrix}+t\begin{bmatrix}-1\\1\\5\end{bmatrix}c=140+t−115 does not intersect r⃗\vec rr. Point TTT is on c⃗\vec cc and SSS is a point on r⃗\vec rr such that TSTSTS is a minimum. By first expressing c⃗\vec cc in parametric form, find an expression for TS→\overrightarrow{TS}TS in terms of ttt.3 marksShort answer
2022TrialQ15 (a) (iii)Show that the line (xyz)=(15−16)+δ(4−1−1)\begin{pmatrix}x\\y\\z\end{pmatrix}=\begin{pmatrix}15\\-1\\6\end{pmatrix}+\delta\begin{pmatrix}4\\-1\\-1\end{pmatrix}xyz=15−16δ4−1−1 is also tangent to the sphere (x−5)2+(y+2)2+(z−3)2=38(x-5)^2+(y+2)^2+(z-3)^2=38(x−5)2+(y+2)2+( by showing that it is perpendicular to the radius of the sphere at (718)\begin{pmatrix}7\\1\\8\end{pmatrix}718.2 marksShort answer
2022TrialQ15 (c) (i)The line has vector equation r⃗=λ[131].\vec r=\lambda\begin{bmatrix}1\\3\\1\end{bmatrix}.r=λ131. For P(x1,y1,z1)P(x_1,y_1,z_1)P(x1,y1,z1), the point QQQ on the line is such that PQPQPQ is a minimum. Using vector projection methods, show that OQ→=x1+3y1+z111[131].\overrightarrow{OQ}=\frac{x_1+3y_1+z_1}{11}\begin{bmatrix}1\\3\\1\end{bmatrix}.OQ=2 marksShort answer
2021HSCQ11 (c)Find the angle between the vectors a⃗=(204)\vec a=\begin{pmatrix}2\\0\\4\end{pmatrix}a=204 and b⃗=(−312)\vec b=\begin{pmatrix}-3\\1\\2\end{pmatrix}b=, giving the angle in degrees correct to 1 decimal place.3 marksShort answer
2021HSCQ16 (a) (ii)Given vectors a⃗=(a1a2a3)\vec a=\begin{pmatrix}a_1\\a_2\\a_3\end{pmatrix}a=a1a2a3 and b⃗=(b1b2b3)\vec b=\begin{pmatrix}b_1\\b_2\\b_3\end{pmatrix}b=, show that ∣a1b1+a2b2+a3b3∣≤a12+a22+a32b12+b22+b32.|a_1b_1+a_2b_2+a_3b_3|\le\sqrt{a_1^2+a_2^2+a_3^2}\sqrt{b_1^2+b_2^2+b_3^2}.∣a1b1+3 marksShort answer
2021HSCQ16 (a) (i)The point P(x,y,z)P(x,y,z)P(x,y,z) lies on the sphere of radius 111 centred at the origin OOO. Using OP→=xi⃗+yj⃗+zk⃗\overrightarrow{OP}=x\vec i+y\vec j+z\vec kOP=xi+y and the triangle inequality, or otherwise, show that ∣x∣+∣y∣+∣z∣≥1.|x|+|y|+|z|\ge1.∣x∣+∣y∣+∣z∣≥1.2 marksShort answer
2021HSCQ16 (a) (iii)As in part (i), P(x,y,z)P(x,y,z)P(x,y,z) lies on the unit sphere centred at the origin. Using part (ii), or otherwise, show that ∣x∣+∣y∣+∣z∣≤3.|x|+|y|+|z|\le\sqrt3.∣x∣+∣y∣+∣z∣≤3.2 marksShort answer
2020HSCQ11 (d)Consider the two vectors u=−2i−j+3k\mathbf u=-2\mathbf i-\mathbf j+3\mathbf ku=−2i−j+3k and v=pi+j+2k\mathbf v=p\mathbf i+\mathbf j+2\mathbf kv=pi+j+2k. For what values of ppp are u−v\mathbf u-\mathbf vu−v and u+v\mathbf u+\mathbf vu+v perpendicular?3 marksShort answer