2022TrialQ16 (c) (i)A projectile is launched from OOO at V m/sV\,\mathrm{m/s}Vm/s so that it will hit the point A(a,b)A(a,b)A(a,b) on the slope. Air resistance is neglected and the acceleration due to gravity is g m/s2g\,\mathrm{m/s^2}gm/s2. Given that y=−gx22V2(1+tan2α)+xtanα,y=-\frac{gx^2}{2V^2}(1+\tan^2\alpha)+x\tan\alpha,y=−2V2gx and that α1<α2\alpha_1<\alpha_2α1<α2, show that tanα1=V2−V4−g2a2−2V2gbga\tan\alpha_1=\frac{V^2-\sqrt{V^4-g^2a^2-2V^2gb}}{ga}tanα1=gaV and tanα2=V2+V4−g2a2−2V2gbga.\tan\alpha_2=\frac{V^2+\sqrt{V^4-g^2a^2-2V^2gb}}{ga}.tanα2=gaV2 marksShort answer
2022TrialQ16 (c) (ii)By showing that tan(α1+α2)=tan(90∘+θ),\tan(\alpha_1+\alpha_2)=\tan(90^\circ+\theta),tan(α1+α2)=tan(90∘+θ), show that ∠COY=∠BOA.\angle COY=\angle BOA.∠COY=∠BOA.4 marksShort answer
2022HSCQ16 (d)Find all the complex numbers z1,z2,z3z_1,z_2,z_3z1,z2,z3 that satisfy the following three conditions simultaneously: ∣z1∣=∣z2∣=∣z3∣,|z_1|=|z_2|=|z_3|,∣z1∣=∣z2∣=∣z z1+z2+z3=1,z_1+z_2+z_3=1,z1+z2+z3 z1z2z3=1.z_1z_2z_3=1.z1z2z3=1.3 marksShort answer
2022TrialQ16 (c)Find ∫lnx−1(x+lnx)2 dx.\int\frac{\ln x-1}{(x+\ln x)^2}\,dx.∫(x+lnx)2lnx−1dx.3 marksShort answer
2022TrialQ16 (b) (ii)Given Sn=133+143+153+⋯+1n3,n≥3,S_n=\frac1{3^3}+\frac1{4^3}+\frac1{5^3}+\cdots+\frac1{n^3},\qquad n\ge3,Sn=331+431+531+⋯+n31,n≥3, use part (i), or otherwise, to prove that Sn<112.S_n<\frac1{12}.Sn<121.3 marksShort answer
2021HSCQ1Four cubes are placed in a line as shown in the diagram. Which vector is equal to AB→+CQ→\overrightarrow{AB}+\overrightarrow{CQ}AB+CQ? A. AQ→\overrightarrow{AQ}AQ B. CP→\overrightarrow{CP}CP C. D. 1 markMultiple choice
2021HSCQ2Which expression is equal to ∫x5e7x dx\int x^5e^{7x}\,dx∫x5e7xdx? A. 17x5e7x−57∫x4e7x dx\frac17x^5e^{7x}-\frac57\int x^4e^{7x}\,dx71x5e7x−7 B. 17x5e7x−57∫x5e7x dx\frac17x^5e^{7x}-\frac57\int x^5e^{7x}\,dx71x5e7x− C. 57x4e7x−57∫x4e7x dx\frac57x^4e^{7x}-\frac57\int x^4e^{7x}\,dx75x4e7x− D. 57x4e7x−57∫x5e7x dx\frac57x^4e^{7x}-\frac57\int x^5e^{7x}\,dx75x4e7x−1 markMultiple choice
2021HSCQ3Which of the following is a vector equation of the line joining A(4,2,5)A(4,2,5)A(4,2,5) and B(−2,2,1)B(-2,2,1)B(−2,2,1)? A. r⃗=(425)+λ(123)\vec r=\begin{pmatrix}4\\2\\5\end{pmatrix}+\lambda\begin{pmatrix}1\\2\\3\end{pmatrix}r=4 B. r⃗=(425)+λ(302)\vec r=\begin{pmatrix}4\\2\\5\end{pmatrix}+\lambda\begin{pmatrix}3\\0\\2\end{pmatrix}r= C. r⃗=(123)+λ(425)\vec r=\begin{pmatrix}1\\2\\3\end{pmatrix}+\lambda\begin{pmatrix}4\\2\\5\end{pmatrix}r= D. r⃗=(302)+λ(425)\vec r=\begin{pmatrix}3\\0\\2\end{pmatrix}+\lambda\begin{pmatrix}4\\2\\5\end{pmatrix}r=1 markMultiple choice
2021HSCQ4Consider the statement: “For all integers nnn, if nnn is a multiple of 666, then nnn is a multiple of 222.” Which is its contrapositive? A. There exists an integer nnn such that nnn is a multiple of 666 and not a multiple of 222. B. There exists an integer nnn such that nnn is a multiple of 222 and not a multiple of 666. C. For all integers nnn, if nnn is not a multiple of 222, then nnn is not a multiple of 666. D. For all integers nnn, if nnn is not a multiple of 666, then nnn is not a multiple of 222.1 markMultiple choice
2021HSCQ5Which of the following statements is FALSE? A. ∀a,b∈R\forall a,b\in\mathbb R∀a,b∈R, a<b⇒a3<b3a<b\Rightarrow a^3<b^3a<b⇒a3<b3. B. ∀a,b∈R\forall a,b\in\mathbb R∀a,b∈R, a<b⇒e−a>e−ba<b\Rightarrow e^{-a}>e^{-b}a<b⇒e−a>e−b. C. ∀a,b∈(0,+∞)\forall a,b\in(0,+\infty)∀a,b∈(0,+∞), a<b⇒lna<lnba<b\Rightarrow\ln a<\ln ba<b⇒lna<lnb. D. ∀a,b∈R\forall a,b\in\mathbb R∀a,b∈R, with a,b≠0a,b\ne0a,b=0, a<b⇒1a>1ba<b\Rightarrow\frac1a>\frac1ba<b⇒a1>b.1 markMultiple choice
2021HSCQ6Which polynomial could have 2+i2+i2+i as a zero, given that kkk is real? A. x3−4x2+kxx^3-4x^2+kxx3−4x2+kx B. x3−4x2+kx+5x^3-4x^2+kx+5x3−4x2+kx+5 C. x3−5x2+kxx^3-5x^2+kxx3−5x2+kx D. x3−5x2+kx+5x^3-5x^2+kx+5x3−5x2+kx+51 markMultiple choice
2021HSCQ7Which diagram best shows the curve described by r⃗(t)=−5cos(t) i⃗+5sin(t) j⃗+t k⃗\vec r(t)=-5\cos(t)\,\vec i+5\sin(t)\,\vec j+t\,\vec kr(t)=−5cos(t)i+5sin(t)j+tk for 0≤t≤4π0\le t\le4\pi0≤t≤4π?1 markMultiple choice
2021HSCQ8A particle is travelling from AAA on the curve joining AAA to BBB. At a particular time, the particle is at PPP and has velocity v⃗\vec vv, as shown. The speed is increasing. Which diagram shows an acceleration a⃗\vec aa that would allow the particle to follow the curve to BBB?1 markMultiple choice
2021HSCQ9Four cards have either RED or BLACK on one side and either WIN or TRY AGAIN on the other side. The visible cards are: Card 1 WIN; Card 2 BLACK; Card 3 TRY AGAIN; Card 4 RED. For the statement “If a card is RED, then it has WIN written on the other side.” What is the minimum number of cards Sam should turn over to check if the statement is true and which cards should be turned over? A. 1 and 4 B. 3 and 4 C. 1, 2 and 4 D. 1, 3 and 41 markMultiple choice
2021HSCQ10Consider the two non-zero complex numbers zzz and www as vectors. Which expression is the projection of zzz onto www? A. Re(zw)∣w∣w\frac{\operatorname{Re}(zw)}{|w|}w∣w∣Re(zw)w B. ∣zw∣w\left|\frac zw\right|wwz C. Re(zw)w\operatorname{Re}\left(\frac zw\right)wRe(wz)w D. Re(z)∣w∣w\frac{\operatorname{Re}(z)}{|w|}w∣w∣Re(z)w1 markMultiple choice
2021HSCQ11 (f)Express 3x2−5(x−2)(x2+x+1)\frac{3x^2-5}{(x-2)(x^2+x+1)}(x−2)(x2+x+1)3x2−5 as a sum of partial fractions over R\mathbb RR.3 marksShort answer
2021HSCQ11 (e)The complex numbers z=5+iz=5+iz=5+i and w=2−4iw=2-4iw=2−4i are given. Find zˉw\frac{\bar z}{w}wzˉ, giving your answer in Cartesian form.2 marksShort answer
2021HSCQ11 (d) (ii)Hence, or otherwise, solve z2+2z+1+i=0z^2+2z+1+i=0z2+2z+1+i=0, giving your solutions in the form a+iba+iba+ib where aaa and bbb are real numbers.2 marksShort answer
2021HSCQ11 (d) (i)Find the two square roots of −i-i−i, giving the answers in the form x+iyx+iyx+iy, where xxx and yyy are real numbers.2 marksShort answer
2021HSCQ11 (c)Find the angle between the vectors a⃗=(204)\vec a=\begin{pmatrix}2\\0\\4\end{pmatrix}a=204 and b⃗=(−312)\vec b=\begin{pmatrix}-3\\1\\2\end{pmatrix}b=, giving the angle in degrees correct to 1 decimal place.3 marksShort answer
2021HSCQ11 (a)The complex numbers z=2eiπ/2z=2e^{i\pi/2}z=2eiπ/2 and w=6eiπ/6w=6e^{i\pi/6}w=6eiπ/6 are given. Find zwzwzw, giving the answer in the form reiθre^{i\theta}reiθ.2 marksShort answer
2021HSCQ12 (b) (i)Consider Statement A: “If n2n^2n2 is even, then nnn is even.” What is the converse of Statement A?1 markShort answer
2021HSCQ12 (e) (i)The diagram shows pyramid ABCDSABCDSABCDS, where ABCDABCDABCD is a square. The diagonals of the square bisect each other at HHH. Show that HA→+HB→+HC→+HD→=0⃗.\overrightarrow{HA}+\overrightarrow{HB}+\overrightarrow{HC}+\overrightarrow{HD}=\vec0.HA+HB+1 markShort answer