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Mathematics Extension 2

Stage 6 · HSC questions by topic

About this subject

Mathematics Extension 2

Atlas organises human-reviewed questions against the NSW Stage 6 Mathematics Extension 2syllabus. Every published question retains its exam source and page.

Syllabus: NESA Stage 6 (2017)
Explore the NESA Stage 6 (2017) syllabus topics

Proof

  • The Nature of Proof
  • Further Proof by Mathematical Induction

Vectors

  • Introduction to three-dimensional vectors
  • Further operations with three-dimensional vectors
  • Vectors and vector equations of lines

Complex Numbers

  • Arithmetic of complex numbers
  • Geometric representation of a complex number
  • Other representations of complex numbers
  • Solving equations with complex numbers
  • Geometrical implications of complex numbers

Calculus

  • Further Integration

Mechanics

  • Simple harmonic motion
  • Modelling motion without resistance
  • Resisted motion
  • Projectiles and resisted motion
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290 questions found

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2020HSC
Q14 (b)

A particle starts from rest and falls through a resisting medium so that its acceleration, in m/s2\mathrm{m/s^2}m/s2, is modelled by
a=10(1−(kv)2),a=10\bigl(1-(kv)^2\bigr), where is the velocity of the particle in and . Find the velocity of the particle after seconds.

a
=
10(1−
(kv)2),

vvv
m/s\mathrm{m/s}m/s
k=0.01k=0.01k=0.01
555
4 marks
Short answer
2020HSC
Q14 (a) (i)

Let z1z_1z1​ be a complex number and let
z2=eiπ/3z1.z_2=e^{i\pi/3}z_1.z2​=eiπ/3z1​.
The diagram shows points AAA and BBB, which represent z1z_1z1​ and z2z_2z2​, respectively, in the Argand plane.

(i) Explain why triangle OABOABOAB is an equilateral triangle.

2 marks
Short answer
2020HSC
Q15 (b) (iii)

Let OPQROPQROPQR be a parallelogram with OP→=p\overrightarrow{OP}=\mathbf pOP=p and OR→=r\overrightarrow{OR}=\mathbf rOR=r. The point SSS is the midpoint of QRQRQR and TTT is the intersection of PRPRPR and OSOSOS, as shown in the diagram.

(iii) Show that
OT→=23r+13p.\overrightarrow{OT}=\frac23\mathbf r+\frac13\mathbf p.OT=32

3 marks
Short answer
2020HSC
Q15 (b) (iv)

Using parts (ii) and (iii), or otherwise, prove that TTT is the point that divides the interval PRPRPR in the ratio 2:12:12:1.

1 mark
Short answer
2020HSC
Q15 (a) (ii)

Using the proposition PPP from part (i), write down the contrapositive of PPP.

1 mark
Short answer
2020HSC
Q15 (a) (i)

In the set of integers, let PPP be the proposition: “If k+1k+1k+1 is divisible by 333, then k3+1k^3+1k3+1 is divisible by $3”.

(i) Prove that the proposition PPP is true.

2 marks
Short answer
2020HSC
Q15 (a) (iii)

Using the proposition PPP from part (i), write down the converse of PPP and state, with reasons, whether this converse is true or false.

3 marks
Short answer
2020HSC
Q15 (b) (i)

The point CCC divides the interval ABABAB so that
CBAC=mn.\frac{CB}{AC}=\frac mn.ACCB​=nm​.
The position vectors of AAA and BBB are a\mathbf aa and b\mathbf bb, respectively, as shown in the diagram.

(i) Show that
AC→=nm+n(b−a).\overrightarrow{AC}=\frac n{m+n}(\mathbf b-\mathbf a).AC=m+n

2 marks
Short answer
2020HSC
Q15 (b) (ii)

Using the same definitions as in part (i), prove that
OC→=mm+na+nm+nb.\overrightarrow{OC}=\frac m{m+n}\mathbf a+\frac n{m+n}\mathbf b.OC=m+nm​a+m+nn​b.

1 mark
Short answer
2020HSC
Q16 (a) (ii)

Given that v<gmkv<\dfrac{gm}{k}v<kgm​, show that when
t=3mkln⁡2,t=\frac{3m}{k}\ln2,t=k3m​ln2,
the velocity of the larger mass is
gm2k.\frac{gm}{2k}.2kgm​.

3 marks
Short answer
2020HSC
Q16 (b) (i)

Let
In=∫0π/2sin⁡2n+1(2θ) dθ,n=0,1,….I_n=\int_0^{\pi/2}\sin^{2n+1}(2\theta)\,d\theta,\qquad n=0,1,\ldots.In​=∫0π/2​sin2n+1(2θ)dθ,n=0,1,….

(i) Prove that
In=2n2n+1In−1,n≥1.I_n=\frac{2n}{2n+1}I_{n-1},\qquad n\geq1.In​=2n+12n​

3 marks
Short answer
2020HSC
Q16 (b) (ii)

Using the result of part (i), deduce that
In=22n(n!)2(2n+1)!.I_n=\frac{2^{2n}(n!)^2}{(2n+1)!}.In​=(2n+1)!22n(n!)2​.

3 marks
Short answer
2020HSC
Q16 (b) (iii)

Let
Jn=∫01xn(1−x)n dx,n=0,1,2,….J_n=\int_0^1x^n(1-x)^n\,dx,\qquad n=0,1,2,\ldots.Jn​=∫01​xn(1−x)ndx,n=0,1,2,….

Using the result of part (ii), or otherwise, show that
Jn=(n!)2(2n+1)!.J_n=\frac{(n!)^2}{(2n+1)!}.Jn​=(2n+1)!(n!

3 marks
Short answer
2020HSC
Q16 (b) (iv)

Prove that
(2nn!)2≤(2n+1)!.\bigl(2^n n!\bigr)^2\leq(2n+1)!.(2nn!)2≤(2n+1)!.

2 marks
Short answer
2020HSC
Q16 (a) (i)

Two masses, 2m2m2m kg and 4m4m4m kg, are attached by a light string. The string is placed over a smooth pulley as shown. The two masses are at rest before being released and vvv is the velocity of the larger mass at time ttt seconds after they are released. The force due to air resistance on each mass has magnitude kvkvkv, where kkk is a positive constant.

(i) Show that
dvdt=gm−kv3m.\frac{dv}{dt}=\frac{gm-kv}{3m}.dtdv​=3m

2 marks
Short answer
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