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Mathematics Extension 2

Stage 6 · HSC questions by topic

About this subject

Mathematics Extension 2

Atlas organises human-reviewed questions against the NSW Stage 6 Mathematics Extension 2syllabus. Every published question retains its exam source and page.

Syllabus: NESA Stage 6 (2017)
Explore the NESA Stage 6 (2017) syllabus topics

Proof

  • The Nature of Proof
  • Further Proof by Mathematical Induction

Vectors

  • Introduction to three-dimensional vectors
  • Further operations with three-dimensional vectors
  • Vectors and vector equations of lines

Complex Numbers

  • Arithmetic of complex numbers
  • Geometric representation of a complex number
  • Other representations of complex numbers
  • Solving equations with complex numbers
  • Geometrical implications of complex numbers

Calculus

  • Further Integration

Mechanics

  • Simple harmonic motion
  • Modelling motion without resistance
  • Resisted motion
  • Projectiles and resisted motion
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13 questions found

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2023HSC
Q7

Which of the following statements about complex numbers is true?

A. For all real numbers x,y,θx,y,\thetax,y,θ with x≠0x\ne0x, for some real number . B. For all non-zero complex numbers , if and , then . C. For all real with , and . D. For all real with and , .

=
0
tan⁡θ=yx⇒x+iy=reiθ\tan\theta=\frac yx\Rightarrow x+iy=re^{i\theta}tanθ=xy​⇒x+iy=reiθ
rrr

z1,z2z_1,z_2z1​,z2​
Arg⁡(z1)=θ1\operatorname{Arg}(z_1)=\theta_1Arg(z1​)=θ1​
Arg⁡(z2)=θ2\operatorname{Arg}(z_2)=\theta_2Arg(z2​)=θ2​
Arg⁡(z1z2)=θ1+θ2\operatorname{Arg}(z_1z_2)=\theta_1+\theta_2Arg(z1​z2​)=θ1​+θ2​

r1,r2,θ1,θ2r_1,r_2,\theta_1,\theta_2r1​,r2​,θ1​,θ2​
r1,r2>0r_1,r_2>0r1​,r2​>0
r1eiθ1=r2eiθ2⇒r1=r2r_1e^{i\theta_1}=r_2e^{i\theta_2}\Rightarrow r_1=r_2r1​eiθ1​=r2​eiθ2​⇒r1​=r2​
θ1=θ2\theta_1=\theta_2θ1​=θ2​

x,y,r,θx,y,r,\thetax,y,r,θ
r>0r>0r>0
x≠0x\ne0x=0
x+iy=reiθ⇒θ=arctan⁡(y/x)x+iy=re^{i\theta}\Rightarrow\theta=\arctan(y/x)x+iy=reiθ⇒θ=arctan(y/x)
1 mark
Multiple choice
2023Trial
Q11 (a)

By first writing 3+i\sqrt{3}+i3​+i and 3−i\sqrt{3}-i3​−i in exponential form, express

(3+i)12+(3−i)12(\sqrt{3}+i)^{12}+(\sqrt{3}-i)^{12}(3​+i)12+

in the form of aba^bab, where aaa and bbb are integers.

2 marks
Short answer
2023Trial
Q12 (a) (iii)

Let α\alphaα be a real number and suppose that zzz is a complex number such that

z+1z=2cos⁡α.z+\frac{1}{z}=2\cos\alpha.z+z1​=2cosα.

You may assume that

zn+1zn=2cos⁡(nα)z^n+\frac{1}{z^n}=2\cos(n\alpha)zn+zn1​=

for all positive integer nnn. Let

ω=z+1z.\omega=z+\frac{1}{z}.ω=z+z1​.

Hence or otherwise, find all solutions of

16(cos⁡α)4+8(cos⁡α)3−12(cos⁡α)2−4cos⁡α+1=0.16(\cos\alpha)^4+8(\cos\alpha)^3-12(\cos\alpha)^2-4\cos\alpha+1=0.16(cosα)4+8(cosα)3−
2 marks
Short answer
2023HSC
Q12 (d)

Find the cube roots of 2−2i2-2i2−2i. Give your answer in exponential form.

3 marks
Short answer
2023Trial
Q13 (a) (ii)

By considering the roots of z3=42(1+i)z^3=4\sqrt{2}(1+i)z3=42​(1+i), show that

cos⁡7π12+cos⁡π12=cos⁡π4.\cos\frac{7\pi}{12}+\cos\frac{\pi}{12}=\cos\frac{\pi}{4}.cos127π​+cos12π​
2 marks
Short answer
2022HSC
Q11 (c) (i)

Write the complex number −3+i-\sqrt3+i−3​+i in exponential form.

2 marks
Short answer
2022Trial
Q16 (a) (i)

Using Euler’s theorem, show that if z=eiθ=cos⁡θ+isin⁡θz=e^{i\theta}=\cos\theta+i\sin\thetaz=eiθ=cosθ+isinθ, then
zn+z−n=2cos⁡nθ.z^n+z^{-n}=2\cos n\theta.zn+z−n=2cosnθ.

1 mark
Short answer
2022Trial
Q16 (a) (ii)

Hence show that
cos⁡7θ=164(cos⁡7θ+7cos⁡5θ+21cos⁡3θ+35cos⁡θ).\cos^7\theta=\frac1{64}\left(\cos7\theta+7\cos5\theta+21\cos3\theta+35\cos\theta\right).cos7θ=641​(cos7θ+7cos5θ+21cos3θ+35cosθ).

2 marks
Short answer
2022Trial
Q16 (a) (i)

Prove that
cos⁡θ+isin⁡θ−1cos⁡θ+isin⁡θ+1=itan⁡θ2.\frac{\cos\theta+i\sin\theta-1}{\cos\theta+i\sin\theta+1}=i\tan\frac\theta2.cosθ+isinθ+1cosθ+isinθ−1​=itan2θ​.

2 marks
Short answer
2021HSC
Q11 (a)

The complex numbers z=2eiπ/2z=2e^{i\pi/2}z=2eiπ/2 and w=6eiπ/6w=6e^{i\pi/6}w=6eiπ/6 are given. Find zwzwzw, giving the answer in the form reiθre^{i\theta}reiθ.

2 marks
Short answer
2021HSC
Q14 (c) (ii)

By using part (i), or otherwise, show that
Re⁡(eiπ/10)=5+58.\operatorname{Re}\left(e^{i\pi/10}\right)=\sqrt{\frac{5+\sqrt5}{8}}.Re(eiπ/10)=85+5​​​.

3 marks
Short answer
2020HSC
Q13 (d) (ii)

By expanding (eiθ+e−iθ)4(e^{i\theta}+e^{-i\theta})^4(eiθ+e−iθ)4, show that
cos⁡4θ=18(cos⁡(4θ)+4cos⁡(2θ)+3).\cos^4\theta=\frac18\bigl(\cos(4\theta)+4\cos(2\theta)+3\bigr).cos4θ=81​(cos

3 marks
Short answer
2020HSC
Q13 (d) (i)

Show that for any integer nnn,
einθ+e−inθ=2cos⁡(nθ).e^{in\theta}+e^{-in\theta}=2\cos(n\theta).einθ+e−inθ=2cos(nθ).

1 mark
Short answer
(3​−
i)12
2
cos
(
n
α
)
12
(
cos
α
)2
−
4cosα+
1=
0.
=
cos4π​.
(
4
θ
)
+
4cos(2θ)+
3).