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Mathematics Extension 2

Stage 6 · HSC questions by topic

About this subject

Mathematics Extension 2

Atlas organises human-reviewed questions against the NSW Stage 6 Mathematics Extension 2syllabus. Every published question retains its exam source and page.

Syllabus: NESA Stage 6 (2017)
Explore the NESA Stage 6 (2017) syllabus topics

Proof

  • The Nature of Proof
  • Further Proof by Mathematical Induction

Vectors

  • Introduction to three-dimensional vectors
  • Further operations with three-dimensional vectors
  • Vectors and vector equations of lines

Complex Numbers

  • Arithmetic of complex numbers
  • Geometric representation of a complex number
  • Other representations of complex numbers
  • Solving equations with complex numbers
  • Geometrical implications of complex numbers

Calculus

  • Further Integration

Mechanics

  • Simple harmonic motion
  • Modelling motion without resistance
  • Resisted motion
  • Projectiles and resisted motion
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58 questions found

List
2023Trial
Q4

Which of the following is an expression for

∫dx7−6x−x2?\int \frac{dx}{\sqrt{7-6x-x^2}}?∫7−6x
−
x2
​
dx
​
?

(A) sin⁡−1(x−32)+C\displaystyle \sin^{-1}\left(\frac{x-3}{2}\right)+Csin−1(2x−3​)+C

(B) sin⁡−1(x+32)+C\displaystyle \sin^{-1}\left(\frac{x+3}{2}\right)+Csin−1(2x+3​)+C

(C) sin⁡−1(x−34)+C\displaystyle \sin^{-1}\left(\frac{x-3}{4}\right)+Csin−1(4x−3​)+C

(D) sin⁡−1(x+34)+C\displaystyle \sin^{-1}\left(\frac{x+3}{4}\right)+Csin−1(4x+3​)+C

1 mark
Multiple choice
2023Trial
Q7

Which expression is equal to

∫3xln⁡x dx?\int 3\sqrt{x}\ln x\,dx?∫3x​lnxdx?

(A) 2xx(ln⁡x−23)+c\displaystyle 2x\sqrt{x}\left(\ln x-\frac{2}{3}\right)+c2xx​(lnx−3

(B) 2xx(ln⁡x+23)+c\displaystyle 2x\sqrt{x}\left(\ln x+\frac{2}{3}\right)+c2xx​(lnx+3

(C) 1x(32ln⁡x−1)+c\displaystyle \frac{1}{\sqrt{x}}\left(\frac{3}{2}\ln x-1\right)+cx​1​

(D) 1x(32ln⁡x+1)+c\displaystyle \frac{1}{\sqrt{x}}\left(\frac{3}{2}\ln x+1\right)+cx​1​

1 mark
Multiple choice
2023Trial
Q12 (b) (i)

Show that

∫0π/2dx1+cos⁡x+sin⁡x=ln⁡2.\int_0^{\pi/2}\frac{dx}{1+\cos x+\sin x}=\ln 2.∫0π/2​1+cosx+sinxdx​=ln2.
3 marks
Short answer
2023Trial
Q12 (c) (iii)

Let

In=∫e−11(1+log⁡ex)n dxI_n=\int_{e^{-1}}^1(1+\log_e x)^n\,dxIn​=∫e−11​(1+loge​x)ndx

and

Jn=∫e−11(log⁡ex)(1+log⁡ex)n dxJ_n=\int_{e^{-1}}^1(\log_e x)(1+\log_e x)^n\,dxJn​=∫e

for n=0,1,2,3,…n=0,1,2,3,\ldotsn=0,1,2,3,….

Hence find the value of J3J_3J3​ in simplest exact form.

2 marks
Short answer
2023Trial
Q12 (c) (i)

Let

In=∫e−11(1+log⁡ex)n dxI_n=\int_{e^{-1}}^1(1+\log_e x)^n\,dxIn​=∫e−11​(1+loge​x)ndx

and

Jn=∫e−11(log⁡ex)(1+log⁡ex)n dxJ_n=\int_{e^{-1}}^1(\log_e x)(1+\log_e x)^n\,dxJn​=∫e

for n=0,1,2,3,…n=0,1,2,3,\ldotsn=0,1,2,3,….

Show that In=1−nIn−1I_n=1-nI_{n-1}In​=1−nIn−1​ for n=1,2,3,….

2 marks
Short answer
2023Trial
Q12 (b) (ii)

By making the substitution u=a−xu=a-xu=a−x, show that

∫0af(x) dx=∫0af(a−x) dx.\int_0^a f(x)\,dx=\int_0^a f(a-x)\,dx.∫0a​f(x)dx=∫0a​f(a−x)dx.
1 mark
Short answer
2023Trial
Q12 (b) (iii)

Hence or otherwise, evaluate

∫0π/2x1+cos⁡x+sin⁡x dx.\int_0^{\pi/2}\frac{x}{1+\cos x+\sin x}\,dx.∫0π/2​1+cosx+sinxx​dx.
2 marks
Short answer
2023Trial
Q12 (c) (ii)

Let

In=∫e−11(1+log⁡ex)n dxI_n=\int_{e^{-1}}^1(1+\log_e x)^n\,dxIn​=∫e−11​(1+loge​x)ndx

and

Jn=∫e−11(log⁡ex)(1+log⁡ex)n dxJ_n=\int_{e^{-1}}^1(\log_e x)(1+\log_e x)^n\,dxJn​=∫e

for n=0,1,2,3,…n=0,1,2,3,\ldotsn=0,1,2,3,….

Show that

Jn=1−(n+2)InJ_n=1-(n+2)I_nJn​=1−(n+2)In​

for n=0,1,2,3,…n=0,1,2,3,\ldotsn=0,1,2,3,….

2 marks
Short answer
2023Trial
Q13 (c) (i)

Find real numbers aaa, bbb and ccc such that

10(x+1)(x2+4)≡ax+1+bx+cx2+4.\frac{10}{(x+1)(x^2+4)}\equiv\frac{a}{x+1}+\frac{bx+c}{x^2+4}.(x+1)(x2+4)10​≡x+1a
3 marks
Short answer
2023Trial
Q13 (c) (ii)

Hence find

∫10(x+1)(x2+4) dx.\int \frac{10}{(x+1)(x^2+4)}\,dx.∫(x+1)(x2+4)10​dx.
2 marks
Short answer
2022HSC
Q4

Of the following expressions, which one need NOT contain a term involving a logarithm in its anti-derivative?

A. x+2x2+4x+5\dfrac{x+2}{x^2+4x+5}x2+4x+5x+2​

B. x+2x2−4x−5\dfrac{x+2}{x^2-4x-5}x2−4x−5x+2​

C. x−1x3−x2+x−1\dfrac{x-1}{x^3-x^2+x-1}x3−x2+x−1x−1​

D. x+1x3−x2+x−1\dfrac{x+1}{x^3-x^2+x-1}x3−x2+x−1x+1​

1 mark
Multiple choice
2022HSC
Q5

If ∫axf(t) dt=g(x)\displaystyle\int_a^x f(t)\,dt=g(x)∫ax​f(t)dt=g(x), which of the following is a primitive of f(x)g(x)f(x)g(x)f(x)g(x)?

A. 12[f(x)]2\frac12[f(x)]^221​[f(x)]2

B. 12[f′(x)]2\frac12[f'(x)]^221​[f′(x)]2

C. 12[g(x)]2\frac12[g(x)]^221​[g(x)]2

D. 12[g′(x)]2\frac12[g'(x)]^221​[g′(x)]2

1 mark
Multiple choice
2022Trial
Q5

∫16x−x2 dx=\int\frac{1}{\sqrt{6x-x^2}}\,dx=∫6x−x2​1​dx=

A. sin⁡−1(x6)+C\sin^{-1}\left(\frac{x}{\sqrt6}\right)+Csin−1(6​

B. sin⁡−1(x6)+C\sin^{-1}\left(\frac{x}{6}\right)+Csin−1(6x​)+C

C. sin⁡−1(x−36)+C\sin^{-1}\left(\frac{x-3}{\sqrt6}\right)+Csin−1(6

D. sin⁡−1(x−33)+C\sin^{-1}\left(\frac{x-3}{3}\right)+Csin−1(3x−3​)+C

1 mark
Multiple choice
2022Trial
Q6

If f(x)f(x)f(x) is even then
∫−aaf(x) dx=\int_{-a}^{a}f(x)\,dx=∫−aa​f(x)dx=

A. 2∫0af(a−x) dx2\int_0^a f(a-x)\,dx2∫0a​f(a−x)dx

B. 2∫0−af(a−x) dx2\int_0^{-a} f(a-x)\,dx2∫0−a​f(a−x)dx

C. 2∫a0f(x) dx2\int_a^0 f(x)\,dx2∫a0​f(x)dx

D. All of the above.

1 mark
Multiple choice
2022Trial
Q7

Which of the following definite integrals has a positive value?

A. ∫−1/21/2x3(1+cos⁡x) dx\displaystyle\int_{-1/2}^{1/2}x^3(1+\cos x)\,dx∫−1/21/2​x3(1+cosx)dx

B. ∫−1/21/2sin⁡−1x1+x4 dx\displaystyle\int_{-1/2}^{1/2}\frac{\sin^{-1}x}{1+x^4}\,dx∫−1/21/2​1+x

C. ∫−1/21/2cos⁡−1xe−x2 dx\displaystyle\int_{-1/2}^{1/2}\frac{\cos^{-1}x}{e^{-x^2}}\,dx∫−1/21/2​e−

D. ∫−1/21/2tan⁡−1xex+e−x dx\displaystyle\int_{-1/2}^{1/2}\frac{\tan^{-1}x}{e^x+e^{-x}}\,dx∫−1/21/2​e

1 mark
Multiple choice
2022Trial
Q11 (e)

Find
∫15+4x−x2 dx.\int\frac{1}{\sqrt{5+4x-x^2}}\,dx.∫5+4x−x2​1​dx.

2 marks
Short answer
2022HSC
Q11 (f)

Using the substitution t=tan⁡x2t=\tan\frac{x}{2}t=tan2x​, find
∫dx1+cos⁡x−sin⁡x.\int\frac{dx}{1+\cos x-\sin x}.∫1+cosx−sinxdx​.

3 marks
Short answer
2022HSC
Q11 (b)

Evaluate ∫sin⁡3(2x)cos⁡(2x) dx\displaystyle\int \sin^3(2x)\cos(2x)\,dx∫sin3(2x)cos(2x)dx.

2 marks
Short answer
2022Trial
Q12 (a) (ii)

Hence, or otherwise, find
∫x2−2xx2−2x−15 dx.\int\frac{x^2-2x}{x^2-2x-15}\,dx.∫x2−2x−15x2−2x​dx.

2 marks
Short answer
2022Trial
Q12 (c) (ii)

Hence find
∫−7x−18(x−1)(x2+4) dx.\int\frac{-7x-18}{(x-1)(x^2+4)}\,dx.∫(x−1)(x2+4)−7x−18​dx.

2 marks
Short answer
2022Trial
Q12 (d) (ii)

Find ∫x−1x+1 dx.\int\sqrt{\frac{x-1}{x+1}}\,dx.∫x+1x−1​​dx.

2 marks
Short answer
2022Trial
Q12 (b)

Evaluate
∫0π/4sec⁡4xtan⁡2x dx.\int_0^{\pi/4}\sec^4x\tan^2x\,dx.∫0π/4​sec4xtan2xdx.

3 marks
Short answer
2022Trial
Q12 (e)

Use the substitution x=2sin⁡θx=2\sin\thetax=2sinθ to find
∫dx(4−x2)3/2.\int\frac{dx}{(4-x^2)^{3/2}}.∫(4−x2)3/2dx​.

3 marks
Short answer
2022Trial
Q12 (a)

Find ∫sin⁡−1(x) dx\displaystyle\int\sin^{-1}(x)\,dx∫sin−1(x)dx.

3 marks
Short answer
2022Trial
Q12 (b)

Find ∫12+cos⁡x dx\displaystyle\int\frac{1}{2+\cos x}\,dx∫2+cosx1​dx.

3 marks
Short answer
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