| Criteria | Marks |
|---|
| Provides correct solution | 4 |
| Finds both stationary points | 3 |
| Finds one of the stationary points, or equivalent merit | 2 |
| Attempts to use quotient rule, or equivalent merit | 1 |
Sample answer:
f(x)f′(x)f′(x)xxy=exx2=e2x2xex−x2ex=e2xxex(2−x)=exx(2−x)=0,2−x=0=0,x=2=0,y=e24=0.541…
| x | −1 | 0 | 1 | 2 | 3 |
|---|
| f′(x) | Negative | 0 | Positive | 0 | Negative |
Minimum at (0,0) and maximum at (2,e24).